742,650
2 × 3 × 52 × 4951
Abundant
Even
Composite
742,650 factors as 2 × 3 × 5^2 × 4951. Its 24 positive divisors give a proper-divisor sum of 1,099,494, so this integer is abundant. The Collatz stopping time is 92 steps.
Prime Factor Structure
Factorization String
2 × 3 × 5^2 × 4951
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
24
Divisor Sum (σ)
1,842,144
Proper Divisor Sum
1,099,494
Digit Sum / Digital Root
24 (Root: 6)
Radix Representation
| Decimal | 742650 |
| Binary | 10110101010011111010 (20 bits) |
| Octal | 0o2652372 |
| Hexadecimal | 0xB54FA |
Divisor Catalog (24)
Collatz Trajectory (92 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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