684,384
25 × 3 × 7129
Abundant
Even
Composite
684,384 factors as 2^5 × 3 × 7129. Its 24 positive divisors give a proper-divisor sum of 1,112,376, so this integer is abundant. The Collatz stopping time is 167 steps.
Prime Factor Structure
Factorization String
2^5 × 3 × 7129
Distinct Prime Factors
3
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
24
Divisor Sum (σ)
1,796,760
Proper Divisor Sum
1,112,376
Digit Sum / Digital Root
33 (Root: 6)
Radix Representation
| Decimal | 684384 |
| Binary | 10100111000101100000 (20 bits) |
| Octal | 0o2470540 |
| Hexadecimal | 0xA7160 |
Divisor Catalog (24)
Collatz Trajectory (167 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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