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6,407,680

29 × 5 × 2503
Abundant Even Composite

6,407,680 factors as 2^9 × 5 × 2503. Its 40 positive divisors give a proper-divisor sum of 8,961,872, so this integer is abundant. The Collatz stopping time is 134 steps.

Prime Factor Structure

Factorization String 2^9 × 5 × 2503
Distinct Prime Factors 3
Square Status No
Abundance Measure Abundant

Analytical Properties

Total Divisors 40
Divisor Sum (σ) 15,369,552
Proper Divisor Sum 8,961,872
Digit Sum / Digital Root 31 (Root: 4)
Adjacent Primes #6407671 ← → #6407701

Radix Representation

Decimal 6407680
Binary 11000011100011000000000 (23 bits)
Octal 0o30343000
Hexadecimal 0x61C600

Divisor Catalog (40)

1 2 4 5 8 10 16 20 32 40 64 80 128 160 256 320 512 640 1,280 2,503 2,560 5,006 10,012 12,515 20,024 25,030 40,048 50,060 80,096 100,120 160,192 200,240 320,384 400,480 640,768 800,960 1,281,536 1,601,920 3,203,840 6,407,680

Collatz Trajectory (134 steps to reach 1)

Iterative sequence n → n/2 (if even) or 3n+1 (if odd):

6,407,680 3,203,840 1,601,920 800,960 400,480 200,240 100,120 50,060 25,030 12,515 37,546 18,773 56,320 28,160 14,080 7,040 3,520 1,760 880 440 220 110 55 166 83 250 125 376 188 94 47 142 71 214 107 322 161 484 242 121 364 182 91 274 137 412 206 103 310 155 466 233 700 350 175 526 263 790 395 1,186

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