616,020
22 × 3 × 5 × 10267
Abundant
Even
Composite
616,020 factors as 2^2 × 3 × 5 × 10267. Its 24 positive divisors give a proper-divisor sum of 1,109,004, so this integer is abundant. The Collatz stopping time is 53 steps.
Prime Factor Structure
Factorization String
2^2 × 3 × 5 × 10267
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
24
Divisor Sum (σ)
1,725,024
Proper Divisor Sum
1,109,004
Digit Sum / Digital Root
15 (Root: 6)
Radix Representation
| Decimal | 616020 |
| Binary | 10010110011001010100 (20 bits) |
| Octal | 0o2263124 |
| Hexadecimal | 0x96654 |
Divisor Catalog (24)
Collatz Trajectory (53 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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