49,660
22 × 5 × 13 × 191
Abundant
Even
Composite
49,660 factors as 2^2 × 5 × 13 × 191. Its 24 positive divisors give a proper-divisor sum of 63,236, so this integer is abundant. The Collatz stopping time is 96 steps.
Prime Factor Structure
Factorization String
2^2 × 5 × 13 × 191
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
24
Divisor Sum (σ)
112,896
Proper Divisor Sum
63,236
Digit Sum / Digital Root
25 (Root: 7)
Radix Representation
| Decimal | 49660 |
| Binary | 1100000111111100 (16 bits) |
| Octal | 0o140774 |
| Hexadecimal | 0xC1FC |
Divisor Catalog (24)
Collatz Trajectory (96 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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