406,760
23 × 5 × 10169
Abundant
Even
Composite
406,760 factors as 2^3 × 5 × 10169. Its 16 positive divisors give a proper-divisor sum of 508,540, so this integer is abundant. The Collatz stopping time is 60 steps.
Prime Factor Structure
Factorization String
2^3 × 5 × 10169
Distinct Prime Factors
3
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
16
Divisor Sum (σ)
915,300
Proper Divisor Sum
508,540
Digit Sum / Digital Root
23 (Root: 5)
Radix Representation
| Decimal | 406760 |
| Binary | 1100011010011101000 (19 bits) |
| Octal | 0o1432350 |
| Hexadecimal | 0x634E8 |
Divisor Catalog (16)
Collatz Trajectory (60 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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