4,020,006
2 × 3 × 670001
Abundant
Even
Composite
4,020,006 factors as 2 × 3 × 670001. Its 8 positive divisors give a proper-divisor sum of 4,020,018, so this integer is abundant. The Collatz stopping time is 185 steps.
Prime Factor Structure
Factorization String
2 × 3 × 670001
Distinct Prime Factors
3
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
8
Divisor Sum (σ)
8,040,024
Proper Divisor Sum
4,020,018
Digit Sum / Digital Root
12 (Root: 3)
Radix Representation
| Decimal | 4020006 |
| Binary | 1111010101011100100110 (22 bits) |
| Octal | 0o17253446 |
| Hexadecimal | 0x3D5726 |
Divisor Catalog (8)
Collatz Trajectory (185 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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