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2,010,160

24 × 5 × 25127
Abundant Even Composite

2,010,160 factors as 2^4 × 5 × 25127. Its 20 positive divisors give a proper-divisor sum of 2,663,648, so this integer is abundant. The Collatz stopping time is 91 steps.

Prime Factor Structure

Factorization String 2^4 × 5 × 25127
Distinct Prime Factors 3
Square Status No
Abundance Measure Abundant

Analytical Properties

Total Divisors 20
Divisor Sum (σ) 4,673,808
Proper Divisor Sum 2,663,648
Digit Sum / Digital Root 10 (Root: 1)
Adjacent Primes #2010139 ← → #2010161

Radix Representation

Decimal 2010160
Binary 111101010110000110000 (21 bits)
Octal 0o7526060
Hexadecimal 0x1EAC30

Divisor Catalog (20)

1 2 4 5 8 10 16 20 40 80 25,127 50,254 100,508 125,635 201,016 251,270 402,032 502,540 1,005,080 2,010,160

Collatz Trajectory (91 steps to reach 1)

Iterative sequence n → n/2 (if even) or 3n+1 (if odd):

2,010,160 1,005,080 502,540 251,270 125,635 376,906 188,453 565,360 282,680 141,340 70,670 35,335 106,006 53,003 159,010 79,505 238,516 119,258 59,629 178,888 89,444 44,722 22,361 67,084 33,542 16,771 50,314 25,157 75,472 37,736 18,868 9,434 4,717 14,152 7,076 3,538 1,769 5,308 2,654 1,327 3,982 1,991 5,974 2,987 8,962 4,481 13,444 6,722 3,361 10,084 5,042 2,521 7,564 3,782 1,891 5,674 2,837 8,512 4,256 2,128

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