2,010,000
24 × 3 × 54 × 67
Abundant
Even
Composite
2,010,000 factors as 2^4 × 3 × 5^4 × 67. Its 100 positive divisors give a proper-divisor sum of 4,575,392, so this integer is abundant. The Collatz stopping time is 91 steps.
Prime Factor Structure
Factorization String
2^4 × 3 × 5^4 × 67
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
100
Divisor Sum (σ)
6,585,392
Proper Divisor Sum
4,575,392
Digit Sum / Digital Root
3 (Root: 3)
Radix Representation
| Decimal | 2010000 |
| Binary | 111101010101110010000 (21 bits) |
| Octal | 0o7525620 |
| Hexadecimal | 0x1EAB90 |
Divisor Catalog (60 of 100)
Collatz Trajectory (91 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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