1,655,240
23 × 5 × 41381
Abundant
Even
Composite
1,655,240 factors as 2^3 × 5 × 41381. Its 16 positive divisors give a proper-divisor sum of 2,069,140, so this integer is abundant. The Collatz stopping time is 145 steps.
Prime Factor Structure
Factorization String
2^3 × 5 × 41381
Distinct Prime Factors
3
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
16
Divisor Sum (σ)
3,724,380
Proper Divisor Sum
2,069,140
Digit Sum / Digital Root
23 (Root: 5)
Radix Representation
| Decimal | 1655240 |
| Binary | 110010100000111001000 (21 bits) |
| Octal | 0o6240710 |
| Hexadecimal | 0x1941C8 |
Divisor Catalog (16)
Collatz Trajectory (145 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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