161,202
2 × 3 × 67 × 401
Abundant
Even
Composite
161,202 factors as 2 × 3 × 67 × 401. Its 16 positive divisors give a proper-divisor sum of 166,830, so this integer is abundant. The Collatz stopping time is 139 steps.
Prime Factor Structure
Factorization String
2 × 3 × 67 × 401
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
16
Divisor Sum (σ)
328,032
Proper Divisor Sum
166,830
Digit Sum / Digital Root
12 (Root: 3)
Radix Representation
| Decimal | 161202 |
| Binary | 100111010110110010 (18 bits) |
| Octal | 0o472662 |
| Hexadecimal | 0x275B2 |
Divisor Catalog (16)
Collatz Trajectory (139 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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