160,880

2⁴ × 5 × 2011

160,880 factors as 2^4 × 5 × 2011. Its 20 positive divisors give a proper-divisor sum of 213,352, so this integer is abundant. The Collatz stopping time is 95 steps.

Prime Factor Structure

Factorization String 2^4 × 5 × 2011

Distinct Prime Factors 3

Square Status No

Abundance Measure Abundant

Analytical Properties

Total Divisors 20

Divisor Sum (σ) 374,232

Proper Divisor Sum 213,352

Digit Sum / Digital Root 23 (Root: 5)

Adjacent Primes #160879 ← → #160883

Radix Representation

Decimal	160880
Binary	100111010001110000 (18 bits)
Octal	0o472160
Hexadecimal	0x27470

Divisor Catalog (20)

1 2 4 5 8 10 16 20 40 80 2,011 4,022 8,044 10,055 16,088 20,110 32,176 40,220 80,440 160,880

Collatz Trajectory (95 steps to reach 1)

Iterative sequence n → n/2 (if even) or 3n+1 (if odd):

160,880 80,440 40,220 20,110 10,055 30,166 15,083 45,250 22,625 67,876 33,938 16,969 50,908 25,454 12,727 38,182 19,091 57,274 28,637 85,912 42,956 21,478 10,739 32,218 16,109 48,328 24,164 12,082 6,041 18,124 9,062 4,531 13,594 6,797 20,392 10,196 5,098 2,549 7,648 3,824 1,912 956 478 239 718 359 1,078 539 1,618 809 2,428 1,214 607 1,822 911 2,734 1,367 4,102 2,051 6,154

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