1,481,064
23 × 3 × 13 × 47 × 101
Abundant
Even
Composite
1,481,064 factors as 2^3 × 3 × 13 × 47 × 101. Its 64 positive divisors give a proper-divisor sum of 2,631,576, so this integer is abundant. The Collatz stopping time is 150 steps.
Prime Factor Structure
Factorization String
2^3 × 3 × 13 × 47 × 101
Distinct Prime Factors
5
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
64
Divisor Sum (σ)
4,112,640
Proper Divisor Sum
2,631,576
Digit Sum / Digital Root
24 (Root: 6)
Radix Representation
| Decimal | 1481064 |
| Binary | 101101001100101101000 (21 bits) |
| Octal | 0o5514550 |
| Hexadecimal | 0x169968 |
Divisor Catalog (60 of 64)
Collatz Trajectory (150 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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