14,101,000
23 × 53 × 59 × 239
Abundant
Even
Composite
14,101,000 factors as 2^3 × 5^3 × 59 × 239. Its 64 positive divisors give a proper-divisor sum of 19,595,000, so this integer is abundant. The Collatz stopping time is 161 steps.
Prime Factor Structure
Factorization String
2^3 × 5^3 × 59 × 239
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
64
Divisor Sum (σ)
33,696,000
Proper Divisor Sum
19,595,000
Digit Sum / Digital Root
7 (Root: 7)
Radix Representation
| Decimal | 14101000 |
| Binary | 110101110010101000001000 (24 bits) |
| Octal | 0o65625010 |
| Hexadecimal | 0xD72A08 |
Divisor Catalog (60 of 64)
Collatz Trajectory (161 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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