1,079,720
23 × 5 × 26993
Abundant
Even
Composite
1,079,720 factors as 2^3 × 5 × 26993. Its 16 positive divisors give a proper-divisor sum of 1,349,740, so this integer is abundant. The Collatz stopping time is 64 steps.
Prime Factor Structure
Factorization String
2^3 × 5 × 26993
Distinct Prime Factors
3
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
16
Divisor Sum (σ)
2,429,460
Proper Divisor Sum
1,349,740
Digit Sum / Digital Root
26 (Root: 8)
Radix Representation
| Decimal | 1079720 |
| Binary | 100000111100110101000 (21 bits) |
| Octal | 0o4074650 |
| Hexadecimal | 0x1079A8 |
Divisor Catalog (16)
Collatz Trajectory (64 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):
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